Chemistry: Class 11 โ€” Chapter 6: Equilibrium

Introduction to Equilibrium

Chemical processes and physical transformations often reach a state of dynamic equilibrium where the rate of the forward process equals the rate of the reverse process. At this stage, the concentrations of reactants and products remain constant over time.

Classification of Chemical Reactions

Based on the extent to which reactions proceed to reach equilibrium, they can be classified into three groups:

  • Reactions that proceed nearly to completion, leaving negligible concentrations of reactants.
  • Reactions in which only small amounts of products are formed, and most of the reactants remain unchanged.
  • Reactions in which the concentrations of reactants and products are comparable at equilibrium.
Equilibrium in Physical Processes

Equilibrium can be established in physical state transformations. These are characterized by a constant value of a physical parameter at a given temperature.

Solid-Liquid Equilibrium

At the melting point of a substance, the solid and liquid phases coexist in dynamic equilibrium. For example, at $273\text{ K}$ and $1\text{ atm}$:

H2O (s) <=> H2O (l)

The temperature at which this occurs under standard atmospheric pressure is called the normal melting point or normal freezing point.

Liquid-Vapour Equilibrium

In a closed vessel, liquid evaporates until the rate of condensation equals the rate of evaporation:

H2O (l) <=> H2O (g)

The pressure exerted by the vapour at this stage is the equilibrium vapour pressure. The temperature at which the vapour pressure equals atmospheric pressure is the normal boiling point.

Solid-Vapour Equilibrium

Sublimable solids establish equilibrium directly with their vapour phase in a closed system:

I2 (solid) <=> I2 (vapour)

Other examples include Camphor and Ammonium Chloride ($NH_4Cl$).

Equilibrium Involving Dissolution of Solids or Gases in Liquids

  • Solids in Liquids: In a saturated solution, a dynamic equilibrium exists between the undissolved solute and the dissolved solute:
    Sugar (solid) <=> Sugar (solution)
  • Gases in Liquids: Governed by Henry's Law, which states that the mass of a gas dissolved in a given mass of solvent at any temperature is proportional to the pressure of the gas above the solvent:
    CO2 (gas) <=> CO2 (in solution)
Equilibrium in Chemical Processes

Analogous to physical systems, chemical reactions in closed vessels attain dynamic equilibrium when the rates of forward and reverse reactions become equal.

Dynamic Nature of Chemical Equilibrium

The dynamic nature of chemical equilibrium can be demonstrated by the synthesis of ammonia using Haber's process with deuterium ($D_2$) instead of dihydrogen ($H_2$). Scrambling of hydrogen and deuterium atoms occurs, proving that both forward and reverse reactions continue to take place at equilibrium.

Student Activity: Demonstrating Dynamic Equilibrium

Aim: To visualize dynamic equilibrium using a simple water transfer model.

Materials Required: Two $100\text{ mL}$ measuring cylinders, two glass tubes of equal or different diameters.

Procedure: Fill cylinder 1 with colored water and keep cylinder 2 empty. Use the tubes to simultaneously transfer water from cylinder 1 to 2, and from cylinder 2 to 1. Repeat until the water levels in both cylinders become constant.

Observation: After several transfers, the water levels in both cylinders reach a constant state, even though water transfer continues in both directions.

Inference: This constancy represents a state of dynamic equilibrium where the rate of transfer in both directions is equal.

Law of Chemical Equilibrium and Equilibrium Constant

The Law of Mass Action states that the rate of a chemical reaction is proportional to the active masses (molar concentrations) of the reacting substances.

The Equilibrium Constant ($K_c$)

For a general reversible reaction:

$$aA + bB \rightleftharpoons cC + dD$$

The equilibrium constant expression is written as:

$$K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}$$

Where $[A]$, $[B]$, $[C]$, and $[D]$ are the equilibrium molar concentrations.

Properties of Equilibrium Constants

  • The equilibrium constant for a reverse reaction is the inverse of the forward reaction: $K'_c = \frac{1}{K_c}$.
  • If the stoichiometric coefficients are multiplied by a factor $n$, the new equilibrium constant becomes $K''_c = (K_c)^n$.
Homogeneous and Heterogeneous Equilibria

Homogeneous Equilibria

All reactants and products are in the same phase. For gaseous systems, the equilibrium constant can be expressed in terms of partial pressures ($K_p$):

$$K_p = \frac{(p_C)^c(p_D)^d}{(p_A)^a(p_B)^b}$$

The relationship between $K_p$ and $K_c$ is given by:

$$K_p = K_c(RT)^{\Delta n}$$

Where $\Delta n = (\text{moles of gaseous products}) - (\text{moles of gaseous reactants})$.

Heterogeneous Equilibria

Reactants and products are present in more than one phase. The concentrations of pure solids and pure liquids are constant and are omitted from the equilibrium constant expression. For example, for the thermal decomposition of calcium carbonate:

$$CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)$$

$$K_c = [CO_2(g)] \quad \text{and} \quad K_p = p_{CO_2}$$

Applications of Equilibrium Constants
Relationship between K, Q and Gibbs Energy

The thermodynamic state of a system is related to the equilibrium constant by the equation:

$$\Delta G = \Delta G^\ominus + RT \ln Q$$

At equilibrium, $\Delta G = 0$ and $Q = K$, which yields:

$$\Delta G^\ominus = -RT \ln K$$

$$K = e^{-\Delta G^\ominus / RT}$$

Factors Affecting Equilibria (Le Chatelier's Principle)

Le Chatelier's Principle states that if a system at equilibrium is subjected to a change in concentration, temperature, or pressure, the system will shift in a direction that tends to undo or counteract the effect of that change.

Effect of Concentration Change

Adding a reactant or removing a product shifts the equilibrium in the forward direction. Removing a reactant or adding a product shifts it in the reverse direction.

Experiment: Reaction of $Fe^{3+}$ and $SCN^-$ ions:

$$Fe^{3+}(aq) + SCN^-(aq) \rightleftharpoons [Fe(SCN)]^{2+}(aq) \quad (\text{Deep Red})$$

  • Adding $KSCN$ increases the red intensity (shifts forward).
  • Adding oxalic acid removes $Fe^{3+}$ as a complex, decreasing red intensity (shifts backward).

Effect of Pressure Change

An increase in pressure shifts the equilibrium toward the side with fewer moles of gas. It has no significant effect on solids or liquids.

Effect of Inert Gas Addition

  • At constant volume: No effect on equilibrium.
  • At constant pressure: Shifts equilibrium in the direction of more gas moles.

Effect of Temperature Change

An increase in temperature favors the endothermic reaction, while a decrease in temperature favors the exothermic reaction.

Experiment: Nitrogen dioxide dimerization:

$$2NO_2(g) \rightleftharpoons N_2O_4(g) \quad \Delta H = -57.2\text{ kJ/mol}$$

  • In hot water ($363\text{ K}$), the brown color of $NO_2$ intensifies (reverse endothermic shift).
  • In a freezing mixture ($270\text{ K}$), the solution becomes colorless due to $N_2O_4$ formation (forward exothermic shift).

Effect of a Catalyst

A catalyst increases the rate of both forward and reverse reactions equally by lowering the activation energy. It does not affect the equilibrium composition or the value of the equilibrium constant.

Ionic Equilibrium in Solution

Equilibrium established between ions and unionized molecules in solution is called ionic equilibrium. Substances that conduct electricity in aqueous solutions are called electrolytes.

Acids, Bases and Salts

Arrhenius Concept

Acids dissociate in water to give hydrogen ions ($H^+$ or hydronium ions $H_3O^+$), and bases produce hydroxyl ions ($OH^-$).

Brรถnsted-Lowry Concept

An acid is a proton donor, and a base is a proton acceptor. When an acid loses a proton, it forms its conjugate base. When a base gains a proton, it forms its conjugate acid.

Lewis Concept

An acid is an electron pair acceptor (e.g., $BF_3$, $AlCl_3$, $H^+$), and a base is an electron pair donor (e.g., $NH_3$, $H_2O$, $OH^-$).

Ionization of Acids and Bases

Ionic Product of Water ($K_w$)

Water undergoes self-ionization:

$$H_2O(l) + H_2O(l) \rightleftharpoons H_3O^+(aq) + OH^-(aq)$$

The ionic product constant of water is:

$$K_w = [H^+][OH^-] = 1.0 \times 10^{-14} \quad \text{at } 298\text{ K}$$

The pH Scale

The acidity or basicity of a solution is expressed using the pH scale:

$$\text{pH} = -\log[H^+]$$

At $298\text{ K}$:

  • Neutral solution: $\text{pH} = 7$
  • Acidic solution: $\text{pH} < 7$
  • Basic solution: $\text{pH} > 7$

Ionization Constants of Weak Acids ($K_a$) and Weak Bases ($K_b$)

For a weak acid $HX$:

$$K_a = \frac{c\alpha^2}{1-\alpha}$$

Where $c$ is the initial concentration and $\alpha$ is the degree of ionization. Similarly, for a weak base:

$$K_b = \frac{c\alpha^2}{1-\alpha}$$

For a conjugate acid-base pair:

$$K_a \times K_b = K_w$$

Common Ion Effect

The suppression of the ionization of a weak electrolyte by the addition of a strong electrolyte containing a common ion is called the common ion effect. For example, adding acetate ions to acetic acid solution decreases $[H^+]$.

Hydrolysis of Salts

The interaction of anions or cations of a salt with water to affect the pH of the solution is called salt hydrolysis:

  • Salts of strong acid and strong base do not hydrolyze (neutral, $\text{pH} = 7$).
  • Salts of strong acid and weak base form acidic solutions ($\text{pH} < 7$).
  • Salts of weak acid and strong base form basic solutions ($\text{pH} > 7$).
  • Salts of weak acid and weak base depend on $pK_a$ and $pK_b$: $\text{pH} = 7 + \frac{1}{2}(pK_a - pK_b)$.
Buffer Solutions

Solutions that resist changes in pH upon dilution or the addition of small amounts of acid or alkali are called buffer solutions.

Henderson-Hasselbalch Equation

For an acidic buffer (weak acid + its salt):

$$\text{pH} = pK_a + \log\frac{[\text{Salt}]}{[\text{Acid}]}$$

For a basic buffer (weak base + its salt):

$$\text{pOH} = pK_b + \log\frac{[\text{Salt}]}{[\text{Base}]}$$

Solubility Equilibria of Sparingly Soluble Salts

For a sparingly soluble salt $M_xX_y$ in equilibrium with its saturated solution:

$$M_xX_y(s) \rightleftharpoons xM^{p+}(aq) + yX^{q-}(aq)$$

The solubility product constant ($K_{sp}$) is given by:

$$K_{sp} = [M^{p+}]^x[X^{q-}]^y$$

If the ionic product ($I_P$) exceeds $K_{sp}$, precipitation occurs. If $I_P < K_{sp}$, more salt dissolves.