Mathematics: Class 8 (Part 1) — Chapter 5: Number Play

5.1 Is This a Multiple Of?

Sum of Consecutive Numbers & Parity

  • Consecutive Sums: Any odd number can be written as the sum of two consecutive natural numbers (e.g., $7 = 3 + 4$).
  • Parity of Expressions: For any four numbers $a, b, c, d$, all combinations of $a \pm b \pm c \pm d$ share the same parity (either all are even or all are odd).
  • Parity Rules:
    • $\text{Odd} \pm \text{Odd} = \text{Even}$
    • $\text{Even} \pm \text{Even} = \text{Even}$
    • $\text{Odd} \pm \text{Even} = \text{Odd}$

Pairs to Make Fours (Divisibility by 4)

  • Even numbers can be classified into two types based on their remainder when divided by 4:
    • Multiples of 4: Expressed as $4p$ (remainder 0).
    • Non-multiples of 4: Expressed as $4p + 2$ (remainder 2).
  • Sum of Two Even Numbers:
    • Divisible by 4 if both are multiples of 4: $4p + 4q = 4(p+q)$.
    • Divisible by 4 if both are non-multiples of 4: $(4p+2) + (4q+2) = 4(p+q+1)$.
    • Not divisible by 4 if one is a multiple of 4 and the other is not: $4p + (4q+2) = 4(p+q) + 2$.
5.2 Checking Divisibility Quickly

Standard Divisibility Rules

  • Divisibility by 10: The units digit must be $0$.
  • Divisibility by 5: The units digit must be $0$ or $5$.
  • Divisibility by 2: The units digit must be even ($0, 2, 4, 6, 8$).
  • Divisibility by 9: The sum of the digits must be divisible by $9$.
  • Divisibility by 3: The sum of the digits must be divisible by $3$.
  • Divisibility by 11: The difference between the sum of digits at odd places and the sum of digits at even places must be $0$ or a multiple of $11$.

Digital Roots

  • Digital Root: The single-digit value obtained by repeatedly adding the digits of a number (e.g., for $489710$: $4+8+9+7+1+0 = 29 \rightarrow 2+9 = 11 \rightarrow 1+1 = 2$).
  • The digital root of any multiple of $9$ is always $9$.
5.3 Digits in Disguise (Cryptarithms)

Rules & Solving Cryptarithms

  • Cryptarithm: A mathematical puzzle where letters stand for unique digits ($0-9$).
  • The leading digit of any number cannot be $0$.
  • Example Puzzle: $AB + 37 = 6A$
    • Since $B + 7$ ends in $A$, and $A + 3 (+ \text{carry}) = 6$, we find $A = 2$ and $B = 5$ ($25 + 37 = 62$).
Summary & Key Properties