Mathematics: Class 8 (Part 2) — Chapter 7: Area

7.1 Rectangles and Squares

Core Concepts & Formulas

  • Area of a Rectangle: Calculated as the product of its length and width.
    $$\text{Area} = \text{length} \times \text{width}$$
  • Unit Squares: Area is measured by finding the number of non-overlapping unit squares (e.g., $1\text{ cm}^2$) that can pack a region.
  • Perimeter vs. Area: Perimeter (boundary length) is not a measure of area. Two regions can have the same perimeter but different areas, or a larger perimeter but smaller area.
  • Dissection: The process of cutting a geometric figure into pieces and rearranging them to form a different figure of equal area.
7.2 Triangles

Formulas & Geometric Properties

  • Area of a Triangle: Derived from half the area of an enclosing rectangle.
    $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$
  • Median Property: In any triangle, the line joining a vertex to the midpoint of its opposite side (the median) divides the triangle into two triangles of equal area.
  • Triangles between Parallel Lines: Triangles with a common base and vertices lying on a line parallel to the base have equal areas (since they share the same base and height).
  • Minimum Perimeter: Among all triangles with a common base and vertices on a parallel line, the isosceles triangle (where the vertex lies on the perpendicular bisector of the base) has the minimum perimeter.
7.3 Polygons, Parallelograms, and Rhombuses

Area of Polygons & Parallelograms

  • Area of any Polygon: Can be evaluated by dividing (triangulating) the polygon into non-overlapping triangles and summing their areas.
  • Area of a Parallelogram: Formulated by dissecting a right triangle from one side and moving it to the other to form a rectangle.
    $$\text{Area} = \text{base} \times \text{height}$$

Area of a Rhombus

  • Area of a Rhombus: Since diagonals of a rhombus are perpendicular bisectors of each other, it can be dissected into a rectangle of equal area.
    $$\text{Area} = \frac{1}{2} \times \text{product of diagonals} = \frac{1}{2} \times d_1 \times d_2$$
7.4 Trapeziums

Area of a Trapezium

  • Area Formula: Derived by splitting the trapezium into a rectangle and two triangles, or by joining two identical copies to form a larger parallelogram.
    $$\text{Area} = \frac{1}{2} \times \text{height} \times \text{sum of parallel sides} = \frac{1}{2} \times h \times (a + b)$$
7.5 Practical Applications & Unit Conversions

Key Conversions & Units

  • Linear Conversions:
    • $1\text{ inch (in)} = 2.54\text{ cm}$
    • $1\text{ foot (ft)} = 12\text{ inches}$
  • Area Conversions:
    • $1\text{ in}^2 = (2.54)^2\text{ cm}^2 = 6.4516\text{ cm}^2$
    • $1\text{ acre} = 43,560\text{ ft}^2$
  • Local Indian Units: Traditional units of land area measurement include bigha, gaj, katha, dhur, cent, and ankanam.
Chapter Summary
  • Triangle Area: $\frac{1}{2} \times \text{base} \times \text{height}$
  • Parallelogram Area: $\text{base} \times \text{height}$
  • Rhombus Area: $\frac{1}{2} \times \text{product of diagonals}$
  • Trapezium Area: $\frac{1}{2} \times \text{height} \times \text{sum of parallel sides}$
  • General Polygons: Solved by breaking down the shape into constituent triangles.