Magnetism is a universal phenomenon permeating cosmic scales, from vast galaxies to subatomic particles. The earth's magnetic field predates human evolution, and the term magnet originates from the Greek island of Magnesia , where magnetic ore deposits (lodestone) were discovered as early as 600 BC.
A bar magnet behaves as a magnetic dipole, closely resembling the magnetic field configuration of a current-carrying finite solenoid.
Magnetic field lines are visual representations used to map the strength and direction of a magnetic field. Their fundamental properties include:
A bar magnet can be modeled as a large number of circulating atomic currents, analogous to a finite solenoid. The axial magnetic field of a finite solenoid of length $2l$, radius $a$, and having $n$ turns per unit length carrying current $I$, at a far axial distance $r$ ($r \gg a$ and $r \gg l$), is given by:
$$B = \frac{\mu_0}{4\pi} \frac{2m}{r^3}$$
where $m = (N I) A = (n \cdot 2l) I (\pi a^2)$ is the total magnetic moment of the solenoid. This expression is mathematically identical to the far axial magnetic field of a bar magnet, establishing their physical equivalence.
When a magnetic dipole of magnetic moment $\vec{m}$ is placed in a uniform magnetic field $\vec{B}$ at an angle $\theta$, it experiences a restoring torque $\vec{\tau}$:
$$\vec{\tau} = \vec{m} \times \vec{B}$$
The magnitude of this torque is:
$$\tau = mB \sin\theta$$
The work done by an external agent in rotating the dipole is stored as magnetic potential energy $U_m$:
$$U_m = \int \tau(\theta) d\theta = \int mB \sin\theta d\theta = -mB \cos\theta = -\vec{m} \cdot \vec{B}$$
Mathematical Problem Statement: A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to $4.5 \times 10^{-2}\text{ J}$. What is the magnitude of the magnetic moment of the magnet?
Step-by-Step Algorithmic Solution Trace:
- Identify the given parameters: torque $\tau = 4.5 \times 10^{-2}\text{ J}$, magnetic field $B = 0.25\text{ T}$, and angle $\theta = 30^\circ$.
- Use the torque formula: $\tau = mB \sin\theta$.
- Isolate the magnetic moment $m$: $$m = \frac{\tau}{B \sin\theta}$$
- Substitute the values into the equation: $$m = \frac{4.5 \times 10^{-2}}{0.25 \times \sin(30^\circ)} = \frac{4.5 \times 10^{-2}}{0.25 \times 0.5} = \frac{4.5 \times 10^{-2}}{0.125}$$
- Calculate the final value: $m = 0.36\text{ J T}^{-1}$.
Final Evaluation Output: $m = \mathbf{0.36\text{ J T}^{-1}}$
The mathematical formulations for magnetic dipoles are directly analogous to those of electric dipoles under specific variable transformations:
| Physical Quantity | Electrostatics | Magnetism |
|---|---|---|
| Constant Factor | $\frac{1}{\varepsilon_0}$ | $\mu_0$ |
| Dipole Moment | $\vec{p}$ | $\vec{m}$ |
| Equatorial Field ($r \gg l$) | $\vec{E}_E = -\frac{\vec{p}}{4\pi\varepsilon_0 r^3}$ | $\vec{B}_E = -\frac{\mu_0 \vec{m}}{4\pi r^3}$ |
| Axial Field ($r \gg l$) | $\vec{E}_A = \frac{2\vec{p}}{4\pi\varepsilon_0 r^3}$ | $\vec{B}_A = \frac{\mu_0 2\vec{m}}{4\pi r^3}$ |
| Torque | $\vec{\tau} = \vec{p} \times \vec{E}$ | $\vec{\tau} = \vec{m} \times \vec{B}$ |
| Potential Energy | $U_e = -\vec{p} \cdot \vec{E}$ | $U_m = -\vec{m} \cdot \vec{B}$ |
Gauss's law for magnetism states that the net magnetic flux $\phi_B$ through any closed surface is always zero. This is a direct consequence of the non-existence of isolated magnetic poles (monopoles).
$$\phi_B = \oint \vec{B} \cdot d\vec{S} = 0$$
In contrast, Gauss's law for electrostatics states that $\oint \vec{E} \cdot d\vec{S} = \frac{q}{\varepsilon_0}$, because isolated electric charges (monopoles) exist. For any closed surface, the number of magnetic field lines entering the surface must exactly equal the number of lines leaving it.
Historical Chronicle: Karl Friedrich Gauss (1777 – 1855)
Conceptual Problem Statement: If magnetic monopoles existed, how would Gauss's law of magnetism be modified?
Step-by-Step Algorithmic Solution Trace:
- Recall the standard Gauss's law for magnetism: $\oint \vec{B} \cdot d\vec{S} = 0$, which assumes zero net magnetic charge inside any closed surface.
- If magnetic monopoles of magnetic charge $q_m$ existed, they would act as sources or sinks of the magnetic field, analogous to electric charges.
- By direct mathematical analogy to Gauss's law for electrostatics ($\oint \vec{E} \cdot d\vec{S} = \frac{q}{\varepsilon_0}$), the surface integral of the magnetic field would be proportional to the enclosed net magnetic charge.
- Using the magnetic constant $\mu_0$, the modified law would be written as: $$\oint \vec{B} \cdot d\vec{S} = \mu_0 q_m$$
Final Evaluation Output: $\oint \vec{B} \cdot d\vec{S} = \mu_0 q_m$
To understand the magnetic behavior of bulk matter, we define several vector fields and parameters:
Mathematical Problem Statement: A solenoid has a core of a material with relative permeability 400 . The windings carry a current of 2 A . If the number of turns is 1000 per metre , calculate: (a) $H$, (b) $M$, and (c) $B$.
Step-by-Step Algorithmic Solution Trace:
- Identify the given values: $\mu_r = 400$, $I = 2\text{ A}$, $n = 1000\text{ turns/m}$.
- Calculate the magnetic intensity $H$: $$H = nI = 1000 \times 2 = 2 \times 10^3\text{ A m}^{-1}$$
- Calculate the total magnetic field $B$: $$B = \mu_r \mu_0 H = 400 \times (4\pi \times 10^{-7}) \times (2 \times 10^3)$$ $$B = 400 \times 1.257 \times 10^{-6} \times 2000 \approx 1.0\text{ T}$$
- Calculate the magnetisation $M$ using $M = (\mu_r - 1)H$: $$M = (400 - 1) \times (2 \times 10^3) = 399 \times 2000 = 7.98 \times 10^5\text{ A m}^{-1} \approx 8 \times 10^5\text{ A m}^{-1}$$
Final Evaluation Output: $H = \mathbf{2 \times 10^3\text{ A m}^{-1}}$, $B = \mathbf{1.0\text{ T}}$, $M = \mathbf{8 \times 10^5\text{ A m}^{-1}}$
Materials are classified into three primary categories based on their response to external magnetic fields and their magnetic susceptibility $\chi$:
| Property / Class | Diamagnetic | Paramagnetic | Ferromagnetic |
|---|---|---|---|
| Susceptibility ($\chi$) | $-1 \le \chi < 0$ (small, negative) | $0 < \chi < \varepsilon$ (small, positive) | $\chi \gg 1$ (large, positive) |
| Relative Permeability ($\mu_r$) | $0 \le \mu_r < 1$ | $1 < \mu_r < 1 + \varepsilon$ | $\mu_r \gg 1$ |
| Permeability ($\mu$) | $\mu < \mu_0$ | $\mu > \mu_0$ | $\mu \gg \mu_0$ |
| Behavior in Field | Repelled weakly; moves to weaker field regions. | Attracted weakly; moves to stronger field regions. | Attracted strongly; aligns strongly with field. |
Diamagnetic substances are repelled by magnets. When placed in an external magnetic field, the field lines are expelled from the material, reducing the internal magnetic field.
Paramagnetic substances get weakly magnetised in the direction of the external magnetic field. Field lines are concentrated inside the material.
Ferromagnetic substances get strongly magnetised in an external magnetic field and are strongly attracted to magnets.
A comprehensive reference of the physical quantities, symbols, dimensions, and SI units introduced in this chapter:
| Physical Quantity | Symbol | Nature | Dimensions | SI Units | Key Formula / Remarks |
|---|---|---|---|---|---|
| Permeability of free space | $\mu_0$ | Scalar | $[MLT^{-2}A^{-2}]$ | $\text{T m A}^{-1}$ | $\mu_0 / 4\pi = 10^{-7}$ |
| Magnetic Field | $\vec{B}$ | Vector | $[MT^{-2}A^{-1}]$ | $\text{T (tesla)}$ | $1\text{ T} = 10^4\text{ gauss}$ |
| Magnetic Moment | $\vec{m}$ | Vector | $[L^2 A]$ | $\text{A m}^2$ or $\text{J T}^{-1}$ | $\vec{\tau} = \vec{m} \times \vec{B}$ |
| Magnetic Flux | $\phi_B$ | Scalar | $[ML^2T^{-2}A^{-1}]$ | $\text{W (weber)}$ | $1\text{ W} = 1\text{ T m}^2$ |
| Magnetisation | $\vec{M}$ | Vector | $[L^{-1}A]$ | $\text{A m}^{-1}$ | $\vec{M} = \vec{m}_{\text{net}} / V$ |
| Magnetic Intensity | $\vec{H}$ | Vector | $[L^{-1}A]$ | $\text{A m}^{-1}$ | $\vec{B} = \mu_0(\vec{H} + \vec{M})$ |
| Magnetic Susceptibility | $\chi$ | Scalar | Dimensionless | None | $\vec{M} = \chi \vec{H}$ |
| Relative Permeability | $\mu_r$ | Scalar | Dimensionless | None | $\mu_r = 1 + \chi$ |